https://www.hackerrank.com/challenges/java-if-else/problem?isFullScreen=true
import java.io.*;
import java.math.*;
import java.security.*;
import java.text.*;
import java.util.*;
import java.util.concurrent.*;
import java.util.regex.*;
public class Solution {
private static final Scanner scanner = new Scanner(System.in);
public static void main(String[] args) {
int N = scanner.nextInt();
scanner.skip("(\r\n|[\n\r\u2028\u2029\u0085])?");
boolean check = 0 < N && N <= 100;
// System.out.println("check :"+ check);
if(check){
if(N%2 == 1){// odd
System.out.println("Weird");
}else if(N%2 == 0){//even
if( 2 <= N && N <= 5){
System.out.println("Not Weird");
}else if( 6 <= N && N <= 20){
System.out.println("Weird");
}else if(20 < N){
System.out.println("Not Weird");
}else{
// System.out.println("Not Weird");
}
}
}
scanner.close();
}
}
In this challenge, we test your knowledge of using if-else conditional statements to automate decision-making processes. An if-else statement has the following logical flow:
Source: Wikipedia
Task
Given an integer, , perform the following conditional actions:
- If is odd, print Weird
- If is even and in the inclusive range of to , print Not Weird
- If is even and in the inclusive range of to , print Weird
- If is even and greater than , print Not Weird
Complete the stub code provided in your editor to print whether or not is weird.
Input Format
A single line containing a positive integer, .
Constraints
Output Format
Print Weird if the number is weird; otherwise, print Not Weird.
Sample Input 0
3
Sample Output 0
Weird
Sample Input 1
24
Sample Output 1
Not Weird
Explanation
Sample Case 0:
is odd and odd numbers are weird, so we print Weird.
Sample Case 1:
and is even, so it isn't weird. Thus, we print Not Weird.
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